-16t^2+1250=0

Solution for -16t^2+1250=0 equation:

-16t^2+1250=0

a = -16; b = 0; c = +1250;
Δ = b2-4ac
Δ = 02-4·(-16)·1250
Δ = 80000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80000}=\sqrt{40000*2}=\sqrt{40000}*\sqrt{2}=200\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{2}}{2*-16}=\frac{0-200\sqrt{2}}{-32}
=-\frac{200\sqrt{2}}{-32}
=-\frac{25\sqrt{2}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{2}}{2*-16}=\frac{0+200\sqrt{2}}{-32}
=\frac{200\sqrt{2}}{-32}
=\frac{25\sqrt{2}}{-4}
$